16x^2-16x=201

Solution for 16x^2-16x=201 equation:

16x^2-16x=201

We move all terms to the left:

16x^2-16x-(201)=0

a = 16; b = -16; c = -201;
Δ = b2-4ac
Δ = -162-4·16·(-201)
Δ = 13120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{13120}=\sqrt{64*205}=\sqrt{64}*\sqrt{205}=8\sqrt{205}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8\sqrt{205}}{2*16}=\frac{16-8\sqrt{205}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8\sqrt{205}}{2*16}=\frac{16+8\sqrt{205}}{32}
$